(3y^2-x)ydx+(x^2-2xy^2)dy=0

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Solution for (3y^2-x)ydx+(x^2-2xy^2)dy=0 equation: 


Simplifying
(3y2 + -1x) * ydx + (x2 + -2xy2) * dy = 0

Reorder the terms:
(-1x + 3y2) * ydx + (x2 + -2xy2) * dy = 0

Reorder the terms for easier multiplication:
dxy(-1x + 3y2) + (x2 + -2xy2) * dy = 0
(-1x * dxy + 3y2 * dxy) + (x2 + -2xy2) * dy = 0

Reorder the terms:
(3dxy3 + -1dx2y) + (x2 + -2xy2) * dy = 0
(3dxy3 + -1dx2y) + (x2 + -2xy2) * dy = 0

Reorder the terms:
3dxy3 + -1dx2y + (-2xy2 + x2) * dy = 0

Reorder the terms for easier multiplication:
3dxy3 + -1dx2y + dy(-2xy2 + x2) = 0
3dxy3 + -1dx2y + (-2xy2 * dy + x2 * dy) = 0
3dxy3 + -1dx2y + (-2dxy3 + dx2y) = 0

Reorder the terms:
3dxy3 + -2dxy3 + -1dx2y + dx2y = 0

Combine like terms: 3dxy3 + -2dxy3 = 1dxy3
1dxy3 + -1dx2y + dx2y = 0

Combine like terms: -1dx2y + dx2y = 0
1dxy3 + 0 = 0
1dxy3 = 0

Solving
1dxy3 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '1'.
dxy3 = 0

Simplifying
dxy3 = 0

The solution to this equation could not be determined.

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